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Neuronal response as a LTI system

A neuronal system can be approximated by a linear, time-invariant system (LTI) with the relevant stimulus s(t) as the input and the observed spike train x(t) as the output:

\begin{displaymath}x(t)=h(t)*s(t)=\int_{t=-\infty}^{\infty} x(t-\tau)s(\tau)d\tau \end{displaymath}

Here the neuron responds to the stimulus s(t) in a particular way specified by the impulse response function h(t).

h(t) can be obtained experimentally by observing the spike train x(t) as the response to the stimulus s(t) by

\begin{displaymath}H(\omega)=\frac{S_{sx}(\omega)}{S_{ss}(\omega)} \end{displaymath}

Specially if the stimulus is white or uncorrelated

\begin{displaymath}r_{ss}(t)=\frac{1}{\sigma^2} \delta(t) \end{displaymath}

its power spectrum becomes a constant

\begin{displaymath}S_{ss}(\omega)=\frac{1}{\sigma^2} \end{displaymath}

and the response spike train has N spikes in time window T

\begin{displaymath}x(t)=\sum_{k=1}^N \delta(t-t_k) \end{displaymath}

then the transfer function $H(\omega)$ can be obtained as

\begin{displaymath}H(\omega)=\frac{S_{sx}(\omega)}{S_{ss}(\omega)} \end{displaymath}

or in time domain
h(t) = $\displaystyle \frac{1}{\sigma^2}r_{sx}(t)
=\frac{1}{\sigma^2} \int_{-\infty}^{\infty}s(\tau-t)x(\tau) d\tau$  
  = $\displaystyle \frac{1}{\sigma^2} \int_{-\infty}^{\infty}s(\tau-t)
\sum_{k=1}^N \delta(\tau-t_k) d\tau
=\frac{1}{\sigma^2} \sum_{k=1}^N s(t_k-t)$  

This is the reverse-correlation formula of h which states that the linear impulse response function of a neuron can be recovered by a simple spike-triggered average of the stimulus preceding the spikes.


next up previous
Next: Neural coding of information Up: Neural Signaling III - Previous: Review of linear, time
Ruye Wang
1999-09-12